3.344 \(\int \frac {x^2}{\sqrt {1-a^2 x^2} \sin ^{-1}(a x)} \, dx\)

Optimal. Leaf size=27 \[ \frac {\log \left (\sin ^{-1}(a x)\right )}{2 a^3}-\frac {\text {Ci}\left (2 \sin ^{-1}(a x)\right )}{2 a^3} \]

[Out]

-1/2*Ci(2*arcsin(a*x))/a^3+1/2*ln(arcsin(a*x))/a^3

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Rubi [A]  time = 0.13, antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {4723, 3312, 3302} \[ \frac {\log \left (\sin ^{-1}(a x)\right )}{2 a^3}-\frac {\text {CosIntegral}\left (2 \sin ^{-1}(a x)\right )}{2 a^3} \]

Antiderivative was successfully verified.

[In]

Int[x^2/(Sqrt[1 - a^2*x^2]*ArcSin[a*x]),x]

[Out]

-CosIntegral[2*ArcSin[a*x]]/(2*a^3) + Log[ArcSin[a*x]]/(2*a^3)

Rule 3302

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosIntegral[e - Pi/2 + f*x]/d, x] /; FreeQ
[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 4723

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[d^p/c^(
m + 1), Subst[Int[(a + b*x)^n*Sin[x]^m*Cos[x]^(2*p + 1), x], x, ArcSin[c*x]], x] /; FreeQ[{a, b, c, d, e, n},
x] && EqQ[c^2*d + e, 0] && IntegerQ[2*p] && GtQ[p, -1] && IGtQ[m, 0] && (IntegerQ[p] || GtQ[d, 0])

Rubi steps

\begin {align*} \int \frac {x^2}{\sqrt {1-a^2 x^2} \sin ^{-1}(a x)} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\sin ^2(x)}{x} \, dx,x,\sin ^{-1}(a x)\right )}{a^3}\\ &=\frac {\operatorname {Subst}\left (\int \left (\frac {1}{2 x}-\frac {\cos (2 x)}{2 x}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{a^3}\\ &=\frac {\log \left (\sin ^{-1}(a x)\right )}{2 a^3}-\frac {\operatorname {Subst}\left (\int \frac {\cos (2 x)}{x} \, dx,x,\sin ^{-1}(a x)\right )}{2 a^3}\\ &=-\frac {\text {Ci}\left (2 \sin ^{-1}(a x)\right )}{2 a^3}+\frac {\log \left (\sin ^{-1}(a x)\right )}{2 a^3}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 22, normalized size = 0.81 \[ \frac {\log \left (\sin ^{-1}(a x)\right )-\text {Ci}\left (2 \sin ^{-1}(a x)\right )}{2 a^3} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2/(Sqrt[1 - a^2*x^2]*ArcSin[a*x]),x]

[Out]

(-CosIntegral[2*ArcSin[a*x]] + Log[ArcSin[a*x]])/(2*a^3)

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fricas [F]  time = 2.06, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {-a^{2} x^{2} + 1} x^{2}}{{\left (a^{2} x^{2} - 1\right )} \arcsin \left (a x\right )}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/arcsin(a*x)/(-a^2*x^2+1)^(1/2),x, algorithm="fricas")

[Out]

integral(-sqrt(-a^2*x^2 + 1)*x^2/((a^2*x^2 - 1)*arcsin(a*x)), x)

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giac [A]  time = 0.55, size = 23, normalized size = 0.85 \[ -\frac {\operatorname {Ci}\left (2 \, \arcsin \left (a x\right )\right )}{2 \, a^{3}} + \frac {\log \left (\arcsin \left (a x\right )\right )}{2 \, a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/arcsin(a*x)/(-a^2*x^2+1)^(1/2),x, algorithm="giac")

[Out]

-1/2*cos_integral(2*arcsin(a*x))/a^3 + 1/2*log(arcsin(a*x))/a^3

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maple [A]  time = 0.00, size = 24, normalized size = 0.89 \[ -\frac {\Ci \left (2 \arcsin \left (a x \right )\right )}{2 a^{3}}+\frac {\ln \left (\arcsin \left (a x \right )\right )}{2 a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/arcsin(a*x)/(-a^2*x^2+1)^(1/2),x)

[Out]

-1/2*Ci(2*arcsin(a*x))/a^3+1/2*ln(arcsin(a*x))/a^3

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2}}{\sqrt {-a^{2} x^{2} + 1} \arcsin \left (a x\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/arcsin(a*x)/(-a^2*x^2+1)^(1/2),x, algorithm="maxima")

[Out]

integrate(x^2/(sqrt(-a^2*x^2 + 1)*arcsin(a*x)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.04 \[ \int \frac {x^2}{\mathrm {asin}\left (a\,x\right )\,\sqrt {1-a^2\,x^2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(asin(a*x)*(1 - a^2*x^2)^(1/2)),x)

[Out]

int(x^2/(asin(a*x)*(1 - a^2*x^2)^(1/2)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2}}{\sqrt {- \left (a x - 1\right ) \left (a x + 1\right )} \operatorname {asin}{\left (a x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/asin(a*x)/(-a**2*x**2+1)**(1/2),x)

[Out]

Integral(x**2/(sqrt(-(a*x - 1)*(a*x + 1))*asin(a*x)), x)

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